JAMB Chemistry past questions and answers
10 questions from the most recent UTME Chemistry papers in our bank, across different topics. Try each one, then open the answer to see a worked solution.
Question 1 · UTME 2024 · Separation of Mixtures and Purification
Fog is a colloid in which
- Aliquid particles are dispersed in a gas medium
- Bgas particles are dispersed in a liquid medium
- Csolid particles are dispersed in a gas medium
- Dgas particles are dispersed in a solid medium
Show answer and solution
Answer: A. liquid particles are dispersed in a gas medium
What the question is asking: Composition of fog.
Key idea: Fog consists of tiny water droplets (liquid) dispersed in air (gas) — a liquid aerosol. Solid in gas is smoke; gas in liquid is foam.
Question 2 · UTME 2024 · Atomic Structure and Bonding
The scientist whose experiments with discharge tubes led to the identification of cathode rays as streams of sub-atomic particles (electrons) is
- AJ. J. Thomson
- BRobert Millikan
- CErnest Rutherford
- DNiels Bohr
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Answer: A. J. J. Thomson
What the question is asking: Discoverer of the electron.
Key idea: In 1897 Thomson deflected cathode rays with electric and magnetic fields and measured their charge-to-mass ratio, showing they were negatively charged particles — electrons. Millikan later measured the electron's charge.
Question 3 · UTME 2024 · Water
In the treatment of water for municipal supply, chlorine is used to
- Aprevent tooth decay
- Bprevent goitre
- Ckill germs
- Dremove colour or odour
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Answer: C. kill germs
What the question is asking: Purpose of chlorination.
Key idea: Chlorine forms HOCl in water, which kills bacteria and other micro-organisms (disinfection). Fluoride prevents tooth decay; charcoal removes colour and odour.
Question 4 · UTME 2024 · Chemical Combination and Stoichiometry
Determine the empirical formula of an oxide of sulphur containing 60% oxygen. [S = 32, O = 16]
- ASO₃
- BSO₂
- CSO₄
- DSO
Show answer and solution
Answer: A. SO₃
What the question is asking: Simplest ratio of S : O.
Step 1 – S = 100 − 60 = 40%
Step 2 – S: 40/32 = 1.25; O: 60/16 = 3.75
Step 3 – Divide by 1.25: 1 : 3 → SO₃
Question 5 · UTME 2024 · Environmental Pollution
Which of the following is an air pollutant?
- AO₂
- BCO
- CH₂O(g)
- DN₂
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Answer: B. CO
What the question is asking: Harmful gas in air.
Key idea: Carbon(II) oxide, from incomplete combustion, is poisonous: it combines with haemoglobin and stops oxygen transport. O₂, N₂ and water vapour are normal, harmless components of air.
Question 6 · UTME 2024 · Energy Changes
For a chemical reaction to be spontaneous, ΔG must be
- Apositive
- Bnegative
- Czero
- Dequal to the enthalpy change
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Answer: B. negative
What the question is asking: Condition for spontaneity.
Key idea: ΔG < 0: spontaneous; ΔG > 0: non-spontaneous; ΔG = 0: at equilibrium.
Question 7 · UTME 2024 · Metals and Their Compounds
The constituents of Alnico are aluminium, nickel, iron and
- AMg
- BCo
- CMn
- DCu
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Answer: B. Co
What the question is asking: Composition of Alnico.
Key idea: The name comes from Al–Ni–Co: aluminium, nickel and cobalt, alloyed with iron. It is used for permanent magnets.
Question 8 · UTME 2024 · Hydrocarbons
The empirical formula of a liquid hydrocarbon is XY. If the relative masses of X and Y in the formula are 72 and 6 respectively, its vapour density is likely to be
- A33
- B66
- C39
- D78
Show answer and solution
Answer: C. 39
What the question is asking: Vapour density from the formula mass.
Step 1 – Formula mass of XY = 72 + 6 = 78 (this is C₆H₆, benzene: 6 × 12 = 72 and 6 × 1 = 6)
Step 2 – Taking the molecular mass as 78, VD = 78/2 = 39
Common trap: 78 is the molar mass, not the vapour density.
Question 9 · UTME 2024 · Acids, Bases and Salts
The pH of a 0.001 mol dm⁻³ solution of H₂SO₄ is [log₁₀ 2 = 0.3]
- A2.7
- B3.0
- C3.3
- D2.0
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Answer: A. 2.7
What the question is asking: pH of a dibasic strong acid.
Step 1 – [H⁺] = 2 × 0.001 = 0.002 = 2 × 10⁻³ mol dm⁻³
Step 2 – pH = −log(2 × 10⁻³) = 3 − 0.3 = 2.7
Question 10 · UTME 2024 · Electrolysis
The quantity of electricity required to deposit 180 g of Ag from molten silver trioxonitrate(V) is [Ag = 108]
- A1.08 F
- B3.30 F
- C1.67 F
- D1.80 F
Show answer and solution
Answer: C. 1.67 F
What the question is asking: Faradays for silver.
Key idea: Ag⁺ + e⁻ → Ag: 1 F per mole of Ag.
Step 1 – Moles Ag = 180/108 = 1.67 mol
Step 2 – Charge = 1.67 F
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